100404013013 has 4 divisors (see below), whose sum is σ = 100418556480. Its totient is φ = 100389469548.

The previous prime is 100404012983. The next prime is 100404013019. The reversal of 100404013013 is 310310404001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100404013013 - 2²² = 100399818709 is a prime.

It is a super-2 number, since 2×100404013013² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100404012982 and 100404013000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100404013019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7261373 + ... + 7275186.

It is an arithmetic number, because the mean of its divisors is an integer number (25104639120).

Almost surely, 2^100404013013 is an apocalyptic number.

It is an amenable number.

100404013013 is a deficient number, since it is larger than the sum of its proper divisors (14543467).

100404013013 is an equidigital number, since it uses as much as digits as its factorization.

100404013013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14543466.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 100404013013 its reverse (310310404001), we get a palindrome (410714417014).

The spelling of 100404013013 in words is "one hundred billion, four hundred four million, thirteen thousand, thirteen".