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10040551342142 = 25020275671071
BaseRepresentation
bin1001001000011011111101…
…1111110000000000111110
31022112212102021201212120012
42102012333133300000332
52304001022120422032
633204322101023222
72054256136146506
oct222067737600076
938485367655505
1010040551342142
1132211a0526622
121161b143b4b12
1357aa874cb129
14269d72a18a06
151262a00356b2
hex921bf7f003e

10040551342142 has 4 divisors (see below), whose sum is σ = 15060827013216. Its totient is φ = 5020275671070.

The previous prime is 10040551342123. The next prime is 10040551342189. The reversal of 10040551342142 is 24124315504001.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 10040551342099 and 10040551342108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2510137835534 + ... + 2510137835537.

It is an arithmetic number, because the mean of its divisors is an integer number (3765206753304).

Almost surely, 210040551342142 is an apocalyptic number.

10040551342142 is a deficient number, since it is larger than the sum of its proper divisors (5020275671074).

10040551342142 is an equidigital number, since it uses as much as digits as its factorization.

10040551342142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5020275671073.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 10040551342142 its reverse (24124315504001), we get a palindrome (34164866846143).

The spelling of 10040551342142 in words is "ten trillion, forty billion, five hundred fifty-one million, three hundred forty-two thousand, one hundred forty-two".

Divisors: 1 2 5020275671071 10040551342142