Base | Representation |
---|---|
bin | 11101001110010001110… |
… | …01011101010010100111 |
3 | 10112222202022022120101120 |
4 | 32213020321131102213 |
5 | 112422343024312401 |
6 | 2045135354225023 |
7 | 132354324126441 |
oct | 16471071352247 |
9 | 3488668276346 |
10 | 1004097885351 |
11 | 357921096900 |
12 | 142726425173 |
13 | 738bc270382 |
14 | 3685479b491 |
15 | 1b1bb3c4836 |
hex | e9c8e5d4a7 |
1004097885351 has 24 divisors (see below), whose sum is σ = 1475412879360. Its totient is φ = 606955200720.
The previous prime is 1004097885341. The next prime is 1004097885353. The reversal of 1004097885351 is 1535887904001.
It is not a de Polignac number, because 1004097885351 - 223 = 1004089496743 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1004097885294 and 1004097885303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1004097885353) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3472081 + ... + 3750138.
It is an arithmetic number, because the mean of its divisors is an integer number (61475536640).
Almost surely, 21004097885351 is an apocalyptic number.
1004097885351 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1004097885351 is a deficient number, since it is larger than the sum of its proper divisors (471314994009).
1004097885351 is a wasteful number, since it uses less digits than its factorization.
1004097885351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7222627 (or 7222616 counting only the distinct ones).
The product of its (nonzero) digits is 1209600, while the sum is 51.
The spelling of 1004097885351 in words is "one trillion, four billion, ninety-seven million, eight hundred eighty-five thousand, three hundred fifty-one".
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