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10041014351335 = 511193945926929
BaseRepresentation
bin1001001000011101101100…
…0101111111010111100111
31022112220121112222011202211
42102013123011333113213
52304002444133220320
633204440040544251
72054303460520522
oct222073305772747
938486545864684
1010041014351335
113221408918250
121162023482087
1357ab2c401276
14269db8301bb9
151262ca9e355a
hex921db17f5e7

10041014351335 has 16 divisors (see below), whose sum is σ = 13212707358240. Its totient is φ = 7264718807040.

The previous prime is 10041014351321. The next prime is 10041014351363. The reversal of 10041014351335 is 53315341014001.

It is a de Polignac number, because none of the positive numbers 2k-10041014351335 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10041014351297 and 10041014351306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 472952850 + ... + 472974079.

It is an arithmetic number, because the mean of its divisors is an integer number (825794209890).

Almost surely, 210041014351335 is an apocalyptic number.

10041014351335 is a deficient number, since it is larger than the sum of its proper divisors (3171693006905).

10041014351335 is a wasteful number, since it uses less digits than its factorization.

10041014351335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 945927138.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 10041014351335 its reverse (53315341014001), we get a palindrome (63356355365336).

The spelling of 10041014351335 in words is "ten trillion, forty-one billion, fourteen million, three hundred fifty-one thousand, three hundred thirty-five".

Divisors: 1 5 11 55 193 965 2123 10615 945926929 4729634645 10405196219 52025981095 182563897297 912819486485 2008202870267 10041014351335