10041122114001 has 18 divisors (see below), whose sum is σ = 15942240713490. Its totient is φ = 6085528553280.

The previous prime is 10041122113999. The next prime is 10041122114011.

10041122114001 is a `hidden beast` number, since 1 + 0 + 0 + 41 + 1 + 221 + 1 + 400 + 1 = 666.

10041122114001 is nontrivially palindromic in base 10.

It can be written as a sum of positive squares in only one way, i.e., 6826075880976 + 3215046233025 = 2612676^2 + 1793055^2 .

It is not a de Polignac number, because 10041122114001 - 2¹ = 10041122113999 is a prime.

It is a super-2 number, since 2×10041122114001² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10041122114011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 4610247816 + ... + 4610249993.

Almost surely, 2^{10041122114001} is an apocalyptic number.

10041122114001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

10041122114001 is a deficient number, since it is larger than the sum of its proper divisors (5901118599489).

10041122114001 is a wasteful number, since it uses less digits than its factorization.

10041122114001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9220497837 (or 9220497823 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

It can be divided in two parts, 1004112 and 2114001, that added together give a palindrome (3118113).

The spelling of 10041122114001 in words is "ten trillion, forty-one billion, one hundred twenty-two million, one hundred fourteen thousand, one".