10041131 has 2 divisors, whose sum is σ = 10041132. Its totient is φ = 10041130.

The previous prime is 10041113. The next prime is 10041167. The reversal of 10041131 is 13114001.

Together with previous prime (10041113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10041131 is a prime.

It is a super-2 number, since 2×10041131² = 201648623518322, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10041191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020565 + 5020566.

It is an arithmetic number, because the mean of its divisors is an integer number (5020566).

Almost surely, 2^10041131 is an apocalyptic number.

10041131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10041131 is an equidigital number, since it uses as much as digits as its factorization.

10041131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 10041131 is about 3168.7743687426. The cubic root of 10041131 is about 215.7384451274.

Adding to 10041131 its reverse (13114001), we get a palindrome (23155132).

The spelling of 10041131 in words is "ten million, forty-one thousand, one hundred thirty-one".