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1004121300103 = 1303797701557
BaseRepresentation
bin11101001110010100100…
…10110001110010000111
310112222210221101011101121
432213022102301302013
5112422420023100403
62045141552134411
7132355030140145
oct16471222616207
93488727334347
101004121300103
11357933329739
12142732237407
13738c407ab5c
1436857934595
151b1bd49c3bd
hexe9ca4b1c87

1004121300103 has 4 divisors (see below), whose sum is σ = 1004129132040. Its totient is φ = 1004113468168.

The previous prime is 1004121300073. The next prime is 1004121300109. The reversal of 1004121300103 is 3010031214001.

1004121300103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1004121300103 - 29 = 1004121299591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1004121300109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3720400 + ... + 3981157.

It is an arithmetic number, because the mean of its divisors is an integer number (251032283010).

Almost surely, 21004121300103 is an apocalyptic number.

1004121300103 is a deficient number, since it is larger than the sum of its proper divisors (7831937).

1004121300103 is an equidigital number, since it uses as much as digits as its factorization.

1004121300103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7831936.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1004121300103 its reverse (3010031214001), we get a palindrome (4014152514104).

The spelling of 1004121300103 in words is "one trillion, four billion, one hundred twenty-one million, three hundred thousand, one hundred three".

Divisors: 1 130379 7701557 1004121300103