Base | Representation |
---|---|
bin | 1001001000011110111010… |
… | …1001111010010110000101 |
3 | 1022112221110102111122012001 |
4 | 2102013232221322112011 |
5 | 2304004132142110140 |
6 | 33204532403025301 |
7 | 2054314554162403 |
oct | 222075651722605 |
9 | 38487412448161 |
10 | 10041342535045 |
11 | 32215670a1558 |
12 | 11620b536b231 |
13 | 57ab823b9403 |
14 | 26a009b30473 |
15 | 1262e971ce9a |
hex | 921eea7a585 |
10041342535045 has 4 divisors (see below), whose sum is σ = 12049611042060. Its totient is φ = 8033074028032.
The previous prime is 10041342535039. The next prime is 10041342535061. The reversal of 10041342535045 is 54053524314001.
10041342535045 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6700482383841 + 3340860151204 = 2588529^2 + 1827802^2 .
It is a cyclic number.
It is not a de Polignac number, because 10041342535045 - 27 = 10041342534917 is a prime.
It is a super-2 number, since 2×100413425350452 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10041342534995 and 10041342535013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1004134253500 + ... + 1004134253509.
It is an arithmetic number, because the mean of its divisors is an integer number (3012402760515).
Almost surely, 210041342535045 is an apocalyptic number.
It is an amenable number.
10041342535045 is a deficient number, since it is larger than the sum of its proper divisors (2008268507015).
10041342535045 is an equidigital number, since it uses as much as digits as its factorization.
10041342535045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2008268507014.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 10041342535045 its reverse (54053524314001), we get a palindrome (64094866849046).
The spelling of 10041342535045 in words is "ten trillion, forty-one billion, three hundred forty-two million, five hundred thirty-five thousand, forty-five".
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