Base | Representation |
---|---|
bin | 10110110101010100101110… |
… | …101001101101000111010111 |
3 | 111011120012012221021122120212 |
4 | 112311110232221231013113 |
5 | 101130301023214014112 |
6 | 553324543230320035 |
7 | 30103131141622205 |
oct | 2665245651550727 |
9 | 434505187248525 |
10 | 100421413032407 |
11 | 29aa7533748775 |
12 | b31a41405901b |
13 | 4405910b2155c |
14 | 1ab25cac02075 |
15 | b922d1000522 |
hex | 5b552ea6d1d7 |
100421413032407 has 2 divisors, whose sum is σ = 100421413032408. Its totient is φ = 100421413032406.
The previous prime is 100421413032373. The next prime is 100421413032433. The reversal of 100421413032407 is 704230314124001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100421413032407 - 216 = 100421412966871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100421413032487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50210706516203 + 50210706516204.
It is an arithmetic number, because the mean of its divisors is an integer number (50210706516204).
Almost surely, 2100421413032407 is an apocalyptic number.
100421413032407 is a deficient number, since it is larger than the sum of its proper divisors (1).
100421413032407 is an equidigital number, since it uses as much as digits as its factorization.
100421413032407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 100421413032407 its reverse (704230314124001), we get a palindrome (804651727156408).
The spelling of 100421413032407 in words is "one hundred trillion, four hundred twenty-one billion, four hundred thirteen million, thirty-two thousand, four hundred seven".
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