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10042203131 = 17923560297
BaseRepresentation
bin10010101101000111…
…11101101111111011
3221220212011202221022
421112203331233323
5131031301000011
64340251133055
7503566214102
oct112643755773
927825152838
1010042203131
11429361a934
121b4314418b
13c40675a3c
146b39cb039
153db9478db
hex2568fdbfb

10042203131 has 4 divisors (see below), whose sum is σ = 10042781352. Its totient is φ = 10041624912.

The previous prime is 10042203113. The next prime is 10042203139. The reversal of 10042203131 is 13130224001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10042203131 - 214 = 10042186747 is a prime.

It is a super-2 number, since 2×100422031312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10042203139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 262226 + ... + 298071.

It is an arithmetic number, because the mean of its divisors is an integer number (2510695338).

Almost surely, 210042203131 is an apocalyptic number.

10042203131 is a deficient number, since it is larger than the sum of its proper divisors (578221).

10042203131 is an equidigital number, since it uses as much as digits as its factorization.

10042203131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 578220.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 10042203131 its reverse (13130224001), we get a palindrome (23172427132).

The spelling of 10042203131 in words is "ten billion, forty-two million, two hundred three thousand, one hundred thirty-one".

Divisors: 1 17923 560297 10042203131