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10042402013 = 71434628859
BaseRepresentation
bin10010101101001001…
…01110010011011101
3221220212112212202022
421112210232103131
5131031323331023
64340255305525
7503601002660
oct112644562335
927825485668
1010042402013
1142937462a6
121b4321b2a5
13c40715417
146b3a3d6d7
153db9867c8
hex25692e4dd

10042402013 has 4 divisors (see below), whose sum is σ = 11477030880. Its totient is φ = 8607773148.

The previous prime is 10042401947. The next prime is 10042402033. The reversal of 10042402013 is 31020424001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10042402013 - 214 = 10042385629 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10042401982 and 10042402000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10042402033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 717314423 + ... + 717314436.

It is an arithmetic number, because the mean of its divisors is an integer number (2869257720).

Almost surely, 210042402013 is an apocalyptic number.

It is an amenable number.

10042402013 is a deficient number, since it is larger than the sum of its proper divisors (1434628867).

10042402013 is an equidigital number, since it uses as much as digits as its factorization.

10042402013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1434628866.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 10042402013 its reverse (31020424001), we get a palindrome (41062826014).

The spelling of 10042402013 in words is "ten billion, forty-two million, four hundred two thousand, thirteen".

Divisors: 1 7 1434628859 10042402013