Base | Representation |
---|---|
bin | 1001001000100011011010… |
… | …1000011100110001100111 |
3 | 1022120001120120202212102211 |
4 | 2102020312220130301213 |
5 | 2304014120312030320 |
6 | 33205252301344251 |
7 | 2054356516334110 |
oct | 222106650346147 |
9 | 38501516685384 |
10 | 10042550111335 |
11 | 3222026802495 |
12 | 1162391868087 |
13 | 57b0156341b1 |
14 | 26a0c2273207 |
15 | 12636a75355a |
hex | 92236a1cc67 |
10042550111335 has 8 divisors (see below), whose sum is σ = 13772640152736. Its totient is φ = 6886320076320.
The previous prime is 10042550111299. The next prime is 10042550111423. The reversal of 10042550111335 is 53311105524001.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10042550111335 - 27 = 10042550111207 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10042550111297 and 10042550111306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 143465001556 + ... + 143465001625.
It is an arithmetic number, because the mean of its divisors is an integer number (1721580019092).
Almost surely, 210042550111335 is an apocalyptic number.
10042550111335 is a deficient number, since it is larger than the sum of its proper divisors (3730090041401).
10042550111335 is an equidigital number, since it uses as much as digits as its factorization.
10042550111335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 286930003193.
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 10042550111335 its reverse (53311105524001), we get a palindrome (63353655635336).
The spelling of 10042550111335 in words is "ten trillion, forty-two billion, five hundred fifty million, one hundred eleven thousand, three hundred thirty-five".
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