1004334042511 has 4 divisors (see below), whose sum is σ = 1014277944024. Its totient is φ = 994390141000.

The previous prime is 1004334042487. The next prime is 1004334042583. The reversal of 1004334042511 is 1152404334001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1004334042511 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1004334042511.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1004334052511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4971950605 + ... + 4971950806.

It is an arithmetic number, because the mean of its divisors is an integer number (253569486006).

Almost surely, 2^{1004334042511} is an apocalyptic number.

1004334042511 is a deficient number, since it is larger than the sum of its proper divisors (9943901513).

1004334042511 is an equidigital number, since it uses as much as digits as its factorization.

1004334042511 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9943901512.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 1004334042511 its reverse (1152404334001), we get a palindrome (2156738376512).

The spelling of 1004334042511 in words is "one trillion, four billion, three hundred thirty-four million, forty-two thousand, five hundred eleven".