Base | Representation |
---|---|
bin | 10010101101010100… |
… | …11111010001000011 |
3 | 221220222101122211021 |
4 | 21112222133101003 |
5 | 131032220211113 |
6 | 4340351530311 |
7 | 503616566005 |
oct | 112652372103 |
9 | 27828348737 |
10 | 10043913283 |
11 | 4294588788 |
12 | 1b43829997 |
13 | c40b24271 |
14 | 6b3d14375 |
15 | 3dbb8448d |
hex | 256a9f443 |
10043913283 has 2 divisors, whose sum is σ = 10043913284. Its totient is φ = 10043913282.
The previous prime is 10043913281. The next prime is 10043913287. The reversal of 10043913283 is 38231934001.
10043913283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10043913283 - 21 = 10043913281 is a prime.
Together with 10043913281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10043913281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021956641 + 5021956642.
It is an arithmetic number, because the mean of its divisors is an integer number (5021956642).
Almost surely, 210043913283 is an apocalyptic number.
10043913283 is a deficient number, since it is larger than the sum of its proper divisors (1).
10043913283 is an equidigital number, since it uses as much as digits as its factorization.
10043913283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 10043913283 in words is "ten billion, forty-three million, nine hundred thirteen thousand, two hundred eighty-three".
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