100440133133 has 4 divisors (see below), whose sum is σ = 100445777568. Its totient is φ = 100434488700.

The previous prime is 100440133109. The next prime is 100440133139. The reversal of 100440133133 is 331331044001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 331331044001 = 179 ⋅1851011419.

It is a cyclic number.

It is not a de Polignac number, because 100440133133 - 2¹² = 100440129037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100440133099 and 100440133108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100440133139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2795441 + ... + 2831142.

It is an arithmetic number, because the mean of its divisors is an integer number (25111444392).

Almost surely, 2^100440133133 is an apocalyptic number.

It is an amenable number.

100440133133 is a deficient number, since it is larger than the sum of its proper divisors (5644435).

100440133133 is an equidigital number, since it uses as much as digits as its factorization.

100440133133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5644434.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 100440133133 its reverse (331331044001), we get a palindrome (431771177134).

The spelling of 100440133133 in words is "one hundred billion, four hundred forty million, one hundred thirty-three thousand, one hundred thirty-three".