Base | Representation |
---|---|
bin | 11101001110111000001… |
… | …11001001101000111111 |
3 | 10120000120202212222120002 |
4 | 32213130013021220333 |
5 | 112424023040220413 |
6 | 2045231351344515 |
7 | 132365320121624 |
oct | 16473407115077 |
9 | 3500522788502 |
10 | 1004420241983 |
11 | 357a77050144 |
12 | 1427b638213b |
13 | 73940c98142 |
14 | 3688551034b |
15 | 1b1d984c958 |
hex | e9dc1c9a3f |
1004420241983 has 2 divisors, whose sum is σ = 1004420241984. Its totient is φ = 1004420241982.
The previous prime is 1004420241973. The next prime is 1004420242031. The reversal of 1004420241983 is 3891420244001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1004420241983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1004420241973) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502210120991 + 502210120992.
It is an arithmetic number, because the mean of its divisors is an integer number (502210120992).
Almost surely, 21004420241983 is an apocalyptic number.
1004420241983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004420241983 is an equidigital number, since it uses as much as digits as its factorization.
1004420241983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 38.
Adding to 1004420241983 its reverse (3891420244001), we get a palindrome (4895840485984).
The spelling of 1004420241983 in words is "one trillion, four billion, four hundred twenty million, two hundred forty-one thousand, nine hundred eighty-three".
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