1005014011 has 2 divisors, whose sum is σ = 1005014012. Its totient is φ = 1005014010.

The previous prime is 1005014009. The next prime is 1005014029. The reversal of 1005014011 is 1104105001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1005014011 - 2¹ = 1005014009 is a prime.

Together with 1005014009, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1005013982 and 1005014000.

It is not a weakly prime, because it can be changed into another prime (1005014051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502507005 + 502507006.

It is an arithmetic number, because the mean of its divisors is an integer number (502507006).

Almost surely, 2^1005014011 is an apocalyptic number.

1005014011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1005014011 is an equidigital number, since it uses as much as digits as its factorization.

1005014011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20, while the sum is 13.

The square root of 1005014011 is about 31701.9559491209. The cubic root of 1005014011 is about 1001.6685513878.

Adding to 1005014011 its reverse (1104105001), we get a palindrome (2109119012).

The spelling of 1005014011 in words is "one billion, five million, fourteen thousand, eleven".