1005014013 has 4 divisors (see below), whose sum is σ = 1340018688. Its totient is φ = 670009340.

The previous prime is 1005014011. The next prime is 1005014029. The reversal of 1005014013 is 3104105001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1005014013 - 2¹ = 1005014011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1005013983 and 1005014001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1005014011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167502333 + ... + 167502338.

It is an arithmetic number, because the mean of its divisors is an integer number (335004672).

Almost surely, 2^1005014013 is an apocalyptic number.

It is an amenable number.

1005014013 is a deficient number, since it is larger than the sum of its proper divisors (335004675).

1005014013 is an equidigital number, since it uses as much as digits as its factorization.

1005014013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 335004674.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 1005014013 is about 31701.9559806647. The cubic root of 1005014013 is about 1001.6685520523.

Adding to 1005014013 its reverse (3104105001), we get a palindrome (4109119014).

The spelling of 1005014013 in words is "one billion, five million, fourteen thousand, thirteen".