100511505014057 has 2 divisors, whose sum is σ = 100511505014058. Its totient is φ = 100511505014056.

The previous prime is 100511505014051. The next prime is 100511505014059. The reversal of 100511505014057 is 750410505115001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96738319198096 + 3773185815961 = 9835564^2 + 1942469^2 .

It is an emirp because it is prime and its reverse (750410505115001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100511505014057 - 2⁴⁰ = 99411993386281 is a prime.

Together with 100511505014059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (100511505014051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50255752507028 + 50255752507029.

It is an arithmetic number, because the mean of its divisors is an integer number (50255752507029).

Almost surely, 2^{100511505014057} is an apocalyptic number.

It is an amenable number.

100511505014057 is a deficient number, since it is larger than the sum of its proper divisors (1).

100511505014057 is an equidigital number, since it uses as much as digits as its factorization.

100511505014057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17500, while the sum is 35.

The spelling of 100511505014057 in words is "one hundred trillion, five hundred eleven billion, five hundred five million, fourteen thousand, fifty-seven".