Base | Representation |
---|---|
bin | 101110110011100000… |
… | …1001011110001100111 |
3 | 100121102220012200221021 |
4 | 1131213001023301213 |
5 | 3121322212031211 |
6 | 114101434032011 |
7 | 10155540046321 |
oct | 1354701136147 |
9 | 317386180837 |
10 | 100512611431 |
11 | 39699826711 |
12 | 17591578607 |
13 | 962aa8bc0b |
14 | 4c1717a611 |
15 | 2934244771 |
hex | 176704bc67 |
100512611431 has 2 divisors, whose sum is σ = 100512611432. Its totient is φ = 100512611430.
The previous prime is 100512611429. The next prime is 100512611453. The reversal of 100512611431 is 134116215001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100512611431 - 21 = 100512611429 is a prime.
It is a super-2 number, since 2×1005126114312 (a number of 23 digits) contains 22 as substring.
Together with 100512611429, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 100512611396 and 100512611405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100512641431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50256305715 + 50256305716.
It is an arithmetic number, because the mean of its divisors is an integer number (50256305716).
Almost surely, 2100512611431 is an apocalyptic number.
100512611431 is a deficient number, since it is larger than the sum of its proper divisors (1).
100512611431 is an equidigital number, since it uses as much as digits as its factorization.
100512611431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 25.
Adding to 100512611431 its reverse (134116215001), we get a palindrome (234628826432).
The spelling of 100512611431 in words is "one hundred billion, five hundred twelve million, six hundred eleven thousand, four hundred thirty-one".
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