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1005141055133 is a prime number
BaseRepresentation
bin11101010000001110001…
…00110101011010011101
310120002110000020002022102
432220013010311122131
5112432012102231013
62045431101054445
7132422221666655
oct16500704653235
93502400202272
101005141055133
11358306a15796
12142977857425
1373a27413ab7
1436913145365
151b22cc81d58
hexea0713569d

1005141055133 has 2 divisors, whose sum is σ = 1005141055134. Its totient is φ = 1005141055132.

The previous prime is 1005141055063. The next prime is 1005141055153. The reversal of 1005141055133 is 3315501415001.

1005141055133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 954398086489 + 50742968644 = 976933^2 + 225262^2 .

It is a cyclic number.

It is not a de Polignac number, because 1005141055133 - 216 = 1005140989597 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1005141055096 and 1005141055105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1005141055153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502570527566 + 502570527567.

It is an arithmetic number, because the mean of its divisors is an integer number (502570527567).

Almost surely, 21005141055133 is an apocalyptic number.

It is an amenable number.

1005141055133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1005141055133 is an equidigital number, since it uses as much as digits as its factorization.

1005141055133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4500, while the sum is 29.

The spelling of 1005141055133 in words is "one trillion, five billion, one hundred forty-one million, fifty-five thousand, one hundred thirty-three".