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1005212114 = 2502606057
BaseRepresentation
bin111011111010100…
…101000111010010
32121001111001210022
4323322211013102
54024313241424
6243425103442
733624106364
oct7372450722
92531431708
101005212114
11476463815
12240787b82
1313034368a
1497706d34
155d3b095e
hex3bea51d2

1005212114 has 4 divisors (see below), whose sum is σ = 1507818174. Its totient is φ = 502606056.

The previous prime is 1005212113. The next prime is 1005212141. The reversal of 1005212114 is 4112125001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4112125001 = 16724623503.

It can be written as a sum of positive squares in only one way, i.e., 950673889 + 54538225 = 30833^2 + 7385^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1005212092 and 1005212101.

It is not an unprimeable number, because it can be changed into a prime (1005212111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251303027 + ... + 251303030.

Almost surely, 21005212114 is an apocalyptic number.

1005212114 is a deficient number, since it is larger than the sum of its proper divisors (502606060).

1005212114 is an equidigital number, since it uses as much as digits as its factorization.

1005212114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 502606059.

The product of its (nonzero) digits is 80, while the sum is 17.

The square root of 1005212114 is about 31705.0802553786. The cubic root of 1005212114 is about 1001.7343615842.

Adding to 1005212114 its reverse (4112125001), we get a palindrome (5117337115).

The spelling of 1005212114 in words is "one billion, five million, two hundred twelve thousand, one hundred fourteen".

Divisors: 1 2 502606057 1005212114