Base | Representation |
---|---|
bin | 1001100010000010… |
… | …00101111000011011 |
3 | 111012122011122211021 |
4 | 10301001011320123 |
5 | 40440014241430 |
6 | 2203442143311 |
7 | 240545435122 |
oct | 46101057033 |
9 | 14178148737 |
10 | 5117337115 |
11 | 2196670130 |
12 | ba9951b37 |
13 | 637262737 |
14 | 3678c6ab9 |
15 | 1ee3d307a |
hex | 131045e1b |
5117337115 has 8 divisors (see below), whose sum is σ = 6699059568. Its totient is φ = 3721699680.
The previous prime is 5117337067. The next prime is 5117337119.
5117337115 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5117337115 - 217 = 5117206043 is a prime.
It is a super-3 number, since 3×51173371153 (a number of 30 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5117337119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46521192 + ... + 46521301.
It is an arithmetic number, because the mean of its divisors is an integer number (837382446).
Almost surely, 25117337115 is an apocalyptic number.
5117337115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5117337115 is a deficient number, since it is larger than the sum of its proper divisors (1581722453).
5117337115 is a wasteful number, since it uses less digits than its factorization.
5117337115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93042509.
The product of its digits is 11025, while the sum is 34.
The square root of 5117337115 is about 71535.5653853382. The cubic root of 5117337115 is about 1723.2488975097.
It can be divided in two parts, 51173 and 37115, that added together give a palindrome (88288).
The spelling of 5117337115 in words is "five billion, one hundred seventeen million, three hundred thirty-seven thousand, one hundred fifteen".
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