Base | Representation |
---|---|
bin | 11101010000111000111… |
… | …10100001100010011011 |
3 | 10120010101000212000100222 |
4 | 32220130132201202123 |
5 | 112433231012023003 |
6 | 2045530444550255 |
7 | 132434141632043 |
oct | 16503436414233 |
9 | 3503330760328 |
10 | 1005500111003 |
11 | 358480665783 |
12 | 142a57b5238b |
13 | 73a8391abab |
14 | 36948acc723 |
15 | 1b24e558c38 |
hex | ea1c7a189b |
1005500111003 has 2 divisors, whose sum is σ = 1005500111004. Its totient is φ = 1005500111002.
The previous prime is 1005500110999. The next prime is 1005500111081. The reversal of 1005500111003 is 3001110055001.
1005500111003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1005500111003 - 22 = 1005500110999 is a prime.
It is a super-2 number, since 2×10055001110032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1005500111093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502750055501 + 502750055502.
It is an arithmetic number, because the mean of its divisors is an integer number (502750055502).
Almost surely, 21005500111003 is an apocalyptic number.
1005500111003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1005500111003 is an equidigital number, since it uses as much as digits as its factorization.
1005500111003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75, while the sum is 17.
Adding to 1005500111003 its reverse (3001110055001), we get a palindrome (4006610166004).
The spelling of 1005500111003 in words is "one trillion, five billion, five hundred million, one hundred eleven thousand, three".
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