1005500111081 has 2 divisors, whose sum is σ = 1005500111082. Its totient is φ = 1005500111080.

The previous prime is 1005500111003. The next prime is 1005500111093. The reversal of 1005500111081 is 1801110055001.

1005500111081 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 591182605456 + 414317505625 = 768884^2 + 643675^2 .

It is a cyclic number.

It is not a de Polignac number, because 1005500111081 - 2¹⁰ = 1005500110057 is a prime.

It is a super-3 number, since 3×1005500111081³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1005700111081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502750055540 + 502750055541.

It is an arithmetic number, because the mean of its divisors is an integer number (502750055541).

Almost surely, 2^{1005500111081} is an apocalyptic number.

It is an amenable number.

1005500111081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1005500111081 is an equidigital number, since it uses as much as digits as its factorization.

1005500111081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 200, while the sum is 23.

Adding to 1005500111081 its reverse (1801110055001), we get a palindrome (2806610166082).

The spelling of 1005500111081 in words is "one trillion, five billion, five hundred million, one hundred eleven thousand, eighty-one".