Base | Representation |
---|---|
bin | 10110110111010000100110… |
… | …000110110100010001011011 |
3 | 111012000220111222102022202122 |
4 | 112313100212012310101123 |
5 | 101134440414343431011 |
6 | 553510020535251455 |
7 | 30115550052354602 |
oct | 2667204606642133 |
9 | 435026458368678 |
10 | 100554413655131 |
11 | 2a048984073097 |
12 | b340151819b8b |
13 | 4415318567b97 |
14 | 1ab8c069d6a39 |
15 | b959b74cc3db |
hex | 5b74261b445b |
100554413655131 has 2 divisors, whose sum is σ = 100554413655132. Its totient is φ = 100554413655130.
The previous prime is 100554413655037. The next prime is 100554413655151. The reversal of 100554413655131 is 131556314455001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100554413655131 is a prime.
It is a super-2 number, since 2×1005544136551312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100554413655151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50277206827565 + 50277206827566.
It is an arithmetic number, because the mean of its divisors is an integer number (50277206827566).
Almost surely, 2100554413655131 is an apocalyptic number.
100554413655131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100554413655131 is an equidigital number, since it uses as much as digits as its factorization.
100554413655131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540000, while the sum is 44.
The spelling of 100554413655131 in words is "one hundred trillion, five hundred fifty-four billion, four hundred thirteen million, six hundred fifty-five thousand, one hundred thirty-one".
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