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100555000495 = 520111000099
BaseRepresentation
bin101110110100110001…
…0111000101010101111
3100121112211222021210121
41131221202320222233
53121414040003440
6114105550345411
710156563254515
oct1355142705257
9317484867717
10100555000495
11397107491a4
12175a37bb267
1396367b0cc1
144c1ca524b5
152937d1934a
hex17698b8aaf

100555000495 has 4 divisors (see below), whose sum is σ = 120666000600. Its totient is φ = 80444000392.

The previous prime is 100555000457. The next prime is 100555000499. The reversal of 100555000495 is 594000555001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100555000495 - 213 = 100554992303 is a prime.

It is a super-2 number, since 2×1005550004952 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 100555000495.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100555000499) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10055500045 + ... + 10055500054.

It is an arithmetic number, because the mean of its divisors is an integer number (30166500150).

Almost surely, 2100555000495 is an apocalyptic number.

100555000495 is a deficient number, since it is larger than the sum of its proper divisors (20111000105).

100555000495 is an equidigital number, since it uses as much as digits as its factorization.

100555000495 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20111000104.

The product of its (nonzero) digits is 22500, while the sum is 34.

Adding to 100555000495 its reverse (594000555001), we get a palindrome (694555555496).

The spelling of 100555000495 in words is "one hundred billion, five hundred fifty-five million, four hundred ninety-five", and thus it is an aban number.

Divisors: 1 5 20111000099 100555000495