Base | Representation |
---|---|
bin | 101110110110100001… |
… | …1111111111000001111 |
3 | 100121200222000101221212 |
4 | 1131231003333320033 |
5 | 3122024141344211 |
6 | 114115455245035 |
7 | 10161210665132 |
oct | 1355503777017 |
9 | 317628011855 |
10 | 100614012431 |
11 | 39740a94799 |
12 | 175bb51977b |
13 | 9645aa32ca |
14 | 4c26814219 |
15 | 293d0c438b |
hex | 176d0ffe0f |
100614012431 has 2 divisors, whose sum is σ = 100614012432. Its totient is φ = 100614012430.
The previous prime is 100614012391. The next prime is 100614012449. The reversal of 100614012431 is 134210416001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 100614012431 - 214 = 100613996047 is a prime.
It is a super-2 number, since 2×1006140124312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 100614012397 and 100614012406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100614012461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50307006215 + 50307006216.
It is an arithmetic number, because the mean of its divisors is an integer number (50307006216).
Almost surely, 2100614012431 is an apocalyptic number.
100614012431 is a deficient number, since it is larger than the sum of its proper divisors (1).
100614012431 is an equidigital number, since it uses as much as digits as its factorization.
100614012431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 100614012431 its reverse (134210416001), we get a palindrome (234824428432).
The spelling of 100614012431 in words is "one hundred billion, six hundred fourteen million, twelve thousand, four hundred thirty-one".
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