Base | Representation |
---|---|
bin | 11101010010011100000… |
… | …00010001000110000101 |
3 | 10120012111221101120211221 |
4 | 32221032000101012011 |
5 | 112441431221241013 |
6 | 2050145130400341 |
7 | 132463551463666 |
oct | 16511600210605 |
9 | 3505457346757 |
10 | 1006331040133 |
11 | 358867701071 |
12 | 14304a2900b1 |
13 | 73b86b0c933 |
14 | 369c71c936d |
15 | 1b29c49008d |
hex | ea4e011185 |
1006331040133 has 2 divisors, whose sum is σ = 1006331040134. Its totient is φ = 1006331040132.
The previous prime is 1006331040089. The next prime is 1006331040151. The reversal of 1006331040133 is 3310401336001.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 899648456004 + 106682584129 = 948498^2 + 326623^2 .
It is a cyclic number.
It is not a de Polignac number, because 1006331040133 - 217 = 1006330909061 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1006331040098 and 1006331040107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1006331040193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 503165520066 + 503165520067.
It is an arithmetic number, because the mean of its divisors is an integer number (503165520067).
Almost surely, 21006331040133 is an apocalyptic number.
It is an amenable number.
1006331040133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1006331040133 is an equidigital number, since it uses as much as digits as its factorization.
1006331040133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1006331040133 its reverse (3310401336001), we get a palindrome (4316732376134).
The spelling of 1006331040133 in words is "one trillion, six billion, three hundred thirty-one million, forty thousand, one hundred thirty-three".
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