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10088093399 is a prime number
BaseRepresentation
bin10010110010100110…
…00001011011010111
3222001001112020112212
421121103001123113
5131130022442044
64345010504035
7504664244006
oct113123013327
928031466485
1010088093399
11430751397a
121b5659501b
13c4a022647
146b9b34c3d
153e09aea9e
hex2594c16d7

10088093399 has 2 divisors, whose sum is σ = 10088093400. Its totient is φ = 10088093398.

The previous prime is 10088093387. The next prime is 10088093417. The reversal of 10088093399 is 99339088001.

10088093399 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (99339088001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10088093399 - 24 = 10088093383 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10088090399) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5044046699 + 5044046700.

It is an arithmetic number, because the mean of its divisors is an integer number (5044046700).

Almost surely, 210088093399 is an apocalyptic number.

10088093399 is a deficient number, since it is larger than the sum of its proper divisors (1).

10088093399 is an equidigital number, since it uses as much as digits as its factorization.

10088093399 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 419904, while the sum is 50.

The spelling of 10088093399 in words is "ten billion, eighty-eight million, ninety-three thousand, three hundred ninety-nine".