Base | Representation |
---|---|
bin | 10010110011111101… |
… | …00001101100001111 |
3 | 222001211222122100222 |
4 | 21121332201230033 |
5 | 131140432411433 |
6 | 4350055141555 |
7 | 505163212556 |
oct | 113176415417 |
9 | 28054878328 |
10 | 10099497743 |
11 | 43129a3155 |
12 | 1b5a3748bb |
13 | c4c4b648a |
14 | 6bb462d9d |
15 | 3e19b3b98 |
hex | 259fa1b0f |
10099497743 has 2 divisors, whose sum is σ = 10099497744. Its totient is φ = 10099497742.
The previous prime is 10099497739. The next prime is 10099497803. The reversal of 10099497743 is 34779499001.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10099497743 - 22 = 10099497739 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10099497143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5049748871 + 5049748872.
It is an arithmetic number, because the mean of its divisors is an integer number (5049748872).
Almost surely, 210099497743 is an apocalyptic number.
10099497743 is a deficient number, since it is larger than the sum of its proper divisors (1).
10099497743 is an equidigital number, since it uses as much as digits as its factorization.
10099497743 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1714608, while the sum is 53.
The spelling of 10099497743 in words is "ten billion, ninety-nine million, four hundred ninety-seven thousand, seven hundred forty-three".
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