1010000010011 has 2 divisors, whose sum is σ = 1010000010012. Its totient is φ = 1010000010010.

The previous prime is 1010000010001. The next prime is 1010000010013. The reversal of 1010000010011 is 1100100000101.

1010000010011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1010000010011 is a prime.

Together with 1010000010013, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1010000009977 and 1010000010004.

It is not a weakly prime, because it can be changed into another prime (1010000010013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505000005005 + 505000005006.

It is an arithmetic number, because the mean of its divisors is an integer number (505000005006).

Almost surely, 2^{1010000010011} is an apocalyptic number.

1010000010011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010000010011 is an equidigital number, since it uses as much as digits as its factorization.

1010000010011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1, while the sum is 5.

Adding to 1010000010011 its reverse (1100100000101), we get a palindrome (2110100010112).

The spelling of 1010000010011 in words is "one trillion, ten billion, ten thousand, eleven".