10100000121303 has 4 divisors (see below), whose sum is σ = 13466666828408. Its totient is φ = 6733333414200.

The previous prime is 10100000121259. The next prime is 10100000121371. The reversal of 10100000121303 is 30312100000101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 10100000121303 - 2¹³ = 10100000113111 is a prime.

It is a super-2 number, since 2×10100000121303² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10100000121373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1683333353548 + ... + 1683333353553.

It is an arithmetic number, because the mean of its divisors is an integer number (3366666707102).

Almost surely, 2^{10100000121303} is an apocalyptic number.

10100000121303 is a deficient number, since it is larger than the sum of its proper divisors (3366666707105).

10100000121303 is an equidigital number, since it uses as much as digits as its factorization.

10100000121303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3366666707104.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 10100000121303 its reverse (30312100000101), we get a palindrome (40412100121404).

The spelling of 10100000121303 in words is "ten trillion, one hundred billion, one hundred twenty-one thousand, three hundred three".