Base | Representation |
---|---|
bin | 10010110100000000… |
… | …11100011010110101 |
3 | 222001212221011221021 |
4 | 21122000130122311 |
5 | 131141100003222 |
6 | 4350114021141 |
7 | 505200405262 |
oct | 113200343265 |
9 | 28055834837 |
10 | 10100000437 |
11 | 43132068aa |
12 | 1b5a5777b1 |
13 | c4c631227 |
14 | 6bb554269 |
15 | 3e1a62ac7 |
hex | 25a01c6b5 |
10100000437 has 2 divisors, whose sum is σ = 10100000438. Its totient is φ = 10100000436.
The previous prime is 10100000431. The next prime is 10100000473. The reversal of 10100000437 is 73400000101.
Together with next prime (10100000473) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6059999716 + 4040000721 = 77846^2 + 63561^2 .
It is a cyclic number.
It is not a de Polignac number, because 10100000437 - 227 = 9965782709 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10100000437.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10100000431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050000218 + 5050000219.
It is an arithmetic number, because the mean of its divisors is an integer number (5050000219).
Almost surely, 210100000437 is an apocalyptic number.
It is an amenable number.
10100000437 is a deficient number, since it is larger than the sum of its proper divisors (1).
10100000437 is an equidigital number, since it uses as much as digits as its factorization.
10100000437 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 16.
Adding to 10100000437 its reverse (73400000101), we get a palindrome (83500000538).
The spelling of 10100000437 in words is "ten billion, one hundred million, four hundred thirty-seven", and thus it is an aban number.
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