10100000431 has 2 divisors, whose sum is σ = 10100000432. Its totient is φ = 10100000430.

The previous prime is 10100000413. The next prime is 10100000437. The reversal of 10100000431 is 13400000101.

It is a happy number.

Together with previous prime (10100000413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10100000431 - 2⁵ = 10100000399 is a prime.

It is a super-2 number, since 2×10100000431² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10100000437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050000215 + 5050000216.

It is an arithmetic number, because the mean of its divisors is an integer number (5050000216).

Almost surely, 2^10100000431 is an apocalyptic number.

10100000431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100000431 is an equidigital number, since it uses as much as digits as its factorization.

10100000431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 10100000431 its reverse (13400000101), we get a palindrome (23500000532).

The spelling of 10100000431 in words is "ten billion, one hundred million, four hundred thirty-one", and thus it is an aban number.