10100121113 has 4 divisors (see below), whose sum is σ = 10112955600. Its totient is φ = 10087286628.

The previous prime is 10100121011. The next prime is 10100121121. The reversal of 10100121113 is 31112100101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10100121113 - 2¹² = 10100117017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10100121094 and 10100121103.

It is not an unprimeable number, because it can be changed into a prime (10100121133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6416063 + ... + 6417636.

It is an arithmetic number, because the mean of its divisors is an integer number (2528238900).

Almost surely, 2^10100121113 is an apocalyptic number.

It is an amenable number.

10100121113 is a deficient number, since it is larger than the sum of its proper divisors (12834487).

10100121113 is an equidigital number, since it uses as much as digits as its factorization.

10100121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12834486.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 10100121113 its reverse (31112100101), we get a palindrome (41212221214).

The spelling of 10100121113 in words is "ten billion, one hundred million, one hundred twenty-one thousand, one hundred thirteen".