Base | Representation |
---|---|
bin | 11101011001010011111… |
… | …00010110001111001111 |
3 | 10120120001002200222101111 |
4 | 32230221330112033033 |
5 | 113022010334001033 |
6 | 2051555223152451 |
7 | 132654155563621 |
oct | 16545174261717 |
9 | 3516032628344 |
10 | 1010021000143 |
11 | 35a3905836a1 |
12 | 1438b9ba5727 |
13 | 7432442971c |
14 | 36c572b4c11 |
15 | 1b4163c17cd |
hex | eb29f163cf |
1010021000143 has 2 divisors, whose sum is σ = 1010021000144. Its totient is φ = 1010021000142.
The previous prime is 1010021000069. The next prime is 1010021000161. The reversal of 1010021000143 is 3410001200101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1010021000143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1010021000243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505010500071 + 505010500072.
It is an arithmetic number, because the mean of its divisors is an integer number (505010500072).
Almost surely, 21010021000143 is an apocalyptic number.
1010021000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010021000143 is an equidigital number, since it uses as much as digits as its factorization.
1010021000143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 1010021000143 its reverse (3410001200101), we get a palindrome (4420022200244).
The spelling of 1010021000143 in words is "one trillion, ten billion, twenty-one million, one hundred forty-three", and thus it is an aban number.
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