10100210411 has 2 divisors, whose sum is σ = 10100210412. Its totient is φ = 10100210410.

The previous prime is 10100210401. The next prime is 10100210441. The reversal of 10100210411 is 11401200101.

It is a weak prime.

It is an emirp because it is prime and its reverse (11401200101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10100210411 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10100210392 and 10100210401.

It is not a weakly prime, because it can be changed into another prime (10100210401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050105205 + 5050105206.

It is an arithmetic number, because the mean of its divisors is an integer number (5050105206).

Almost surely, 2^10100210411 is an apocalyptic number.

10100210411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100210411 is an equidigital number, since it uses as much as digits as its factorization.

10100210411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 10100210411 its reverse (11401200101), we get a palindrome (21501410512).

The spelling of 10100210411 in words is "ten billion, one hundred million, two hundred ten thousand, four hundred eleven".