10100213131 has 2 divisors, whose sum is σ = 10100213132. Its totient is φ = 10100213130.

The previous prime is 10100213113. The next prime is 10100213147. The reversal of 10100213131 is 13131200101.

Together with previous prime (10100213113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10100213131 - 2³¹ = 7952729483 is a prime.

It is a super-2 number, since 2×10100213131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10100213161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050106565 + 5050106566.

It is an arithmetic number, because the mean of its divisors is an integer number (5050106566).

Almost surely, 2^10100213131 is an apocalyptic number.

10100213131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100213131 is an equidigital number, since it uses as much as digits as its factorization.

10100213131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10100213131 its reverse (13131200101), we get a palindrome (23231413232).

The spelling of 10100213131 in words is "ten billion, one hundred million, two hundred thirteen thousand, one hundred thirty-one".