10100213147 has 2 divisors, whose sum is σ = 10100213148. Its totient is φ = 10100213146.

The previous prime is 10100213131. The next prime is 10100213153. The reversal of 10100213147 is 74131200101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10100213147 - 2⁴ = 10100213131 is a prime.

It is a super-2 number, since 2×10100213147² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10100513147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050106573 + 5050106574.

It is an arithmetic number, because the mean of its divisors is an integer number (5050106574).

Almost surely, 2^10100213147 is an apocalyptic number.

10100213147 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100213147 is an equidigital number, since it uses as much as digits as its factorization.

10100213147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

Adding to 10100213147 its reverse (74131200101), we get a palindrome (84231413248).

The spelling of 10100213147 in words is "ten billion, one hundred million, two hundred thirteen thousand, one hundred forty-seven".