10100213311 has 4 divisors (see below), whose sum is σ = 10221902712. Its totient is φ = 9978523912.

The previous prime is 10100213309. The next prime is 10100213317. The reversal of 10100213311 is 11331200101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10100213311 - 2¹ = 10100213309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10100213291 and 10100213300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10100213317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60844576 + ... + 60844741.

It is an arithmetic number, because the mean of its divisors is an integer number (2555475678).

Almost surely, 2^10100213311 is an apocalyptic number.

10100213311 is a deficient number, since it is larger than the sum of its proper divisors (121689401).

10100213311 is an equidigital number, since it uses as much as digits as its factorization.

10100213311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121689400.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10100213311 its reverse (11331200101), we get a palindrome (21431413412).

The spelling of 10100213311 in words is "ten billion, one hundred million, two hundred thirteen thousand, three hundred eleven".