101003113102013 has 2 divisors, whose sum is σ = 101003113102014. Its totient is φ = 101003113102012.

The previous prime is 101003113101971. The next prime is 101003113102033. The reversal of 101003113102013 is 310201311300101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74601880268644 + 26401232833369 = 8637238^2 + 5138213^2 .

It is a cyclic number.

It is not a de Polignac number, because 101003113102013 - 2⁶ = 101003113101949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101003113101982 and 101003113102000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101003113102033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50501556551006 + 50501556551007.

It is an arithmetic number, because the mean of its divisors is an integer number (50501556551007).

Almost surely, 2^{101003113102013} is an apocalyptic number.

It is an amenable number.

101003113102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101003113102013 is an equidigital number, since it uses as much as digits as its factorization.

101003113102013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 101003113102013 its reverse (310201311300101), we get a palindrome (411204424402114).

The spelling of 101003113102013 in words is "one hundred one trillion, three billion, one hundred thirteen million, one hundred two thousand, thirteen".