Base | Representation |
---|---|
bin | 101111000010001000… |
… | …0011000000010111111 |
3 | 100122201002012210012012 |
4 | 1132010100120002333 |
5 | 3123323300224434 |
6 | 114222235401435 |
7 | 10203644315600 |
oct | 1360420300277 |
9 | 318632183165 |
10 | 101003133119 |
11 | 399206a9939 |
12 | 176a98b327b |
13 | 96a85a5a35 |
14 | 4c62385da7 |
15 | 29623393ce |
hex | 17844180bf |
101003133119 has 6 divisors (see below), whose sum is σ = 117493440624. Its totient is φ = 86574114060.
The previous prime is 101003133037. The next prime is 101003133157. The reversal of 101003133119 is 911331300101.
It is not a de Polignac number, because 101003133119 - 28 = 101003132863 is a prime.
It is a super-2 number, since 2×1010031331192 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 101003133094 and 101003133103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101003133019) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1030644167 + ... + 1030644264.
It is an arithmetic number, because the mean of its divisors is an integer number (19582240104).
Almost surely, 2101003133119 is an apocalyptic number.
101003133119 is a deficient number, since it is larger than the sum of its proper divisors (16490307505).
101003133119 is an equidigital number, since it uses as much as digits as its factorization.
101003133119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2061288445 (or 2061288438 counting only the distinct ones).
The product of its (nonzero) digits is 243, while the sum is 23.
The spelling of 101003133119 in words is "one hundred one billion, three million, one hundred thirty-three thousand, one hundred nineteen".
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