1010032031213 has 4 divisors (see below), whose sum is σ = 1012056144000. Its totient is φ = 1008007918428.

The previous prime is 1010032031209. The next prime is 1010032031221. The reversal of 1010032031213 is 3121302300101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1010032031213 - 2² = 1010032031209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1010032031191 and 1010032031200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1010032031513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1012055645 + ... + 1012056642.

It is an arithmetic number, because the mean of its divisors is an integer number (253014036000).

Almost surely, 2^{1010032031213} is an apocalyptic number.

It is an amenable number.

1010032031213 is a deficient number, since it is larger than the sum of its proper divisors (2024112787).

1010032031213 is an equidigital number, since it uses as much as digits as its factorization.

1010032031213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2024112786.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 1010032031213 its reverse (3121302300101), we get a palindrome (4131334331314).

The spelling of 1010032031213 in words is "one trillion, ten billion, thirty-two million, thirty-one thousand, two hundred thirteen".