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101003242013 is a prime number
BaseRepresentation
bin101111000010001000…
…0110010101000011101
3100122201002102022120022
41132010100302220131
53123323312221023
6114222242001525
710203645251222
oct1360420625035
9318632368508
10101003242013
1139920773733
12176a99462a5
1396a861347b
144c623b3949
15296235b7c8
hex1784432a1d

101003242013 has 2 divisors, whose sum is σ = 101003242014. Its totient is φ = 101003242012.

The previous prime is 101003242001. The next prime is 101003242049. The reversal of 101003242013 is 310242300101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87732662809 + 13270579204 = 296197^2 + 115198^2 .

It is an emirp because it is prime and its reverse (310242300101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101003242013 - 220 = 101002193437 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101003241982 and 101003242000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101003241013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50501621006 + 50501621007.

It is an arithmetic number, because the mean of its divisors is an integer number (50501621007).

Almost surely, 2101003242013 is an apocalyptic number.

It is an amenable number.

101003242013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101003242013 is an equidigital number, since it uses as much as digits as its factorization.

101003242013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 101003242013 its reverse (310242300101), we get a palindrome (411245542114).

The spelling of 101003242013 in words is "one hundred one billion, three million, two hundred forty-two thousand, thirteen".