1010047631 has 2 divisors, whose sum is σ = 1010047632. Its totient is φ = 1010047630.

The previous prime is 1010047613. The next prime is 1010047651. The reversal of 1010047631 is 1367400101.

1010047631 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (1010047613) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (1367400101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1010047631 - 2²² = 1005853327 is a prime.

It is a super-2 number, since 2×1010047631² = 2040392433777424322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1010047597 and 1010047606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1010047651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505023815 + 505023816.

It is an arithmetic number, because the mean of its divisors is an integer number (505023816).

Almost surely, 2^1010047631 is an apocalyptic number.

1010047631 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010047631 is an equidigital number, since it uses as much as digits as its factorization.

1010047631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 1010047631 is about 31781.2465299900. The cubic root of 1010047631 is about 1003.3380553218.

Adding to 1010047631 its reverse (1367400101), we get a palindrome (2377447732).

The spelling of 1010047631 in words is "one billion, ten million, forty-seven thousand, six hundred thirty-one".