101010101011007 has 2 divisors, whose sum is σ = 101010101011008. Its totient is φ = 101010101011006.

The previous prime is 101010101010967. The next prime is 101010101011009. The reversal of 101010101011007 is 700110101010101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101010101011007 - 2³² = 101005806043711 is a prime.

Together with 101010101011009, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101010101010982 and 101010101011000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101010101011009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505050505503 + 50505050505504.

It is an arithmetic number, because the mean of its divisors is an integer number (50505050505504).

Almost surely, 2^{101010101011007} is an apocalyptic number.

101010101011007 is a deficient number, since it is larger than the sum of its proper divisors (1).

101010101011007 is an equidigital number, since it uses as much as digits as its factorization.

101010101011007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7, while the sum is 14.

Adding to 101010101011007 its reverse (700110101010101), we get a palindrome (801120202021108).

The spelling of 101010101011007 in words is "one hundred one trillion, ten billion, one hundred one million, eleven thousand, seven".