Base | Representation |
---|---|
bin | 1001001011111101100001… |
… | …1110100011001100011011 |
3 | 1022202122201000201101102211 |
4 | 2102333120132203030123 |
5 | 2310444023100000102 |
6 | 33252214204535551 |
7 | 2061531450226051 |
oct | 222773036431433 |
9 | 38678630641384 |
10 | 10101100000027 |
11 | 3244941684453 |
12 | 11717b1b515b7 |
13 | 5836b681894a |
14 | 26cc782cc1d1 |
15 | 127b45a137d7 |
hex | 92fd87a331b |
10101100000027 has 2 divisors, whose sum is σ = 10101100000028. Its totient is φ = 10101100000026.
The previous prime is 10101100000007. The next prime is 10101100000051. The reversal of 10101100000027 is 72000000110101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10101100000027 - 27 = 10101099999899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10101099999962 and 10101100000016.
It is not a weakly prime, because it can be changed into another prime (10101100000007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050550000013 + 5050550000014.
It is an arithmetic number, because the mean of its divisors is an integer number (5050550000014).
Almost surely, 210101100000027 is an apocalyptic number.
10101100000027 is a deficient number, since it is larger than the sum of its proper divisors (1).
10101100000027 is an equidigital number, since it uses as much as digits as its factorization.
10101100000027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 13.
Adding to 10101100000027 its reverse (72000000110101), we get a palindrome (82101100110128).
The spelling of 10101100000027 in words is "ten trillion, one hundred one billion, one hundred million, twenty-seven", and thus it is an aban number.
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