10101100000051 has 2 divisors, whose sum is σ = 10101100000052. Its totient is φ = 10101100000050.

The previous prime is 10101100000027. The next prime is 10101100000063. The reversal of 10101100000051 is 15000000110101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10101100000051 - 2⁷ = 10101099999923 is a prime.

It is a super-2 number, since 2×10101100000051² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10101099999983 and 10101100000037.

It is not a weakly prime, because it can be changed into another prime (10101100000151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050550000025 + 5050550000026.

It is an arithmetic number, because the mean of its divisors is an integer number (5050550000026).

Almost surely, 2^{10101100000051} is an apocalyptic number.

10101100000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

10101100000051 is an equidigital number, since it uses as much as digits as its factorization.

10101100000051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5, while the sum is 10.

Adding to 10101100000051 its reverse (15000000110101), we get a palindrome (25101100110152).

The spelling of 10101100000051 in words is "ten trillion, one hundred one billion, one hundred million, fifty-one", and thus it is an aban number.