Base | Representation |
---|---|
bin | 10110111101111001111010… |
… | …101111000000101001110111 |
3 | 111020122120022020100221110222 |
4 | 112331321322233000221313 |
5 | 101214431213100324002 |
6 | 554455505253004555 |
7 | 30163545136343615 |
oct | 2675717257005167 |
9 | 436576266327428 |
10 | 101011100011127 |
11 | 2a204626669789 |
12 | b3b476502375b |
13 | 44493c8c849b7 |
14 | 1ad2d6b5206b5 |
15 | ba27e577d1a2 |
hex | 5bde7abc0a77 |
101011100011127 has 2 divisors, whose sum is σ = 101011100011128. Its totient is φ = 101011100011126.
The previous prime is 101011100011061. The next prime is 101011100011223. The reversal of 101011100011127 is 721110001110101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101011100011127 - 214 = 101011099994743 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101011100011727) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505550005563 + 50505550005564.
It is an arithmetic number, because the mean of its divisors is an integer number (50505550005564).
Almost surely, 2101011100011127 is an apocalyptic number.
101011100011127 is a deficient number, since it is larger than the sum of its proper divisors (1).
101011100011127 is an equidigital number, since it uses as much as digits as its factorization.
101011100011127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14, while the sum is 17.
Adding to 101011100011127 its reverse (721110001110101), we get a palindrome (822121101121228).
The spelling of 101011100011127 in words is "one hundred one trillion, eleven billion, one hundred million, eleven thousand, one hundred twenty-seven".
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